MCA Ist sem /MCSL-017/Solved Assignment/C And Assembly Language Programming /2017-2018 New

Q.1.
A.1.

Section 1: C Programming Lab

Structure is a user-defined data type in C which allows you to combine different data types to store a particular type of record. Structure helps to construct a complex data type in more meaningful way. It is somewhat similar to an Array. The only difference is that array is used to store collection of similar datatypes while structure can store collection of any type of data.

Structure is used to represent a record. Suppose you want to store record of Student which consists of student name, address, roll number and age. You can define a structure to hold this information.

Array of Structure:

We can declare an array of structure. Each element of the array representing a  structure variable. Example : struct employee emp[5];

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

#define size 200

struct emp

{

    int emp_id;

    char *emp_name;

  char *Dept_name;

  float Salary;

  char *Pos;

 int Date;

}*emp1, *emp3;

void create();

void display();

void update();

void delete();

FILE *fp, *fp1;

int count = 0;

void main(int argc, char **argv)

{

    int i, n, ch;

    printf("1] Create a Record\n");

    printf("2] Display Records\n");

    printf("3] Update Records\n");

    printf(“4] Delete Records\n”);

    printf("4] Exit");

    while (1)

    {

        printf("\nEnter your choice : ");

        scanf("%d", &ch);

        switch (ch)

        {

        case 1:   

            fp = fopen(argv[1], "a");

            create();

            break;

        case 2:   

            fp1 = fopen(argv[1],"rb");

            display();

            break;

        case 3:   

            fp1 = fopen(argv[1], "r+");

            update();

            break;

        case 4:

            exit(0);

        }

    }

}

/* To create an employee record */

void create()

{

    int i;

    char *p;

    emp1 = (struct emp *)malloc(sizeof(struct emp));

    emp1->emp_name = (char *)malloc((size)*(sizeof(char)));

emp1 = (struct emp *)malloc(sizeof(struct emp));

    emp1->Dept_name = (char *)malloc((size)*(sizeof(char)));

emp1 = (struct emp *)malloc(sizeof(struct emp));

    emp1->Pos = (char *)malloc((size)*(sizeof(char)));

    printf("Enter name of employee : ");

    scanf(" %[^\n]s", emp1-> emp_name);

    printf("Enter emp id : ");

    scanf(" %d", &emp1-> emp_id);

printf("Enter name of the Department: ");

    scanf(" %[^\n]s", emp1-> Dept_name);

    printf("Enter Salary : ");

    scanf(" %d", &emp1-> Salary);

printf("Enter Position: ");

    scanf(" %[^\n]s", emp1-> Pos);

    printf("Enter Date of Joining : ");

    scanf(" %d", &emp1->Date);

    fwrite(&emp1->emp_id, sizeof(emp1->emp_id), 1, fp);

    fwrite(emp1->emp_name, size, 1, fp);

    fwrite(&emp1->Dept_name, sizeof(emp1-> Dept_name), 1, fp);

    fwrite(emp1-> Dept_name, size, 1, fp);

    fwrite(&emp1-> salary, sizeof(emp1-> salary), 1, fp);

    fwrite(emp1-> salary, size, 1, fp);

    fwrite(&emp1->Pos, sizeof(emp1-> Pos), 1, fp);

    fwrite(emp1-> Pos, size, 1, fp);

    fwrite(&emp1->Date, sizeof(emp1-> Date), 1, fp);

    fwrite(emp1-> Date, size, 1, fp);

    count++;   // count to number of entries of records

    fclose(fp);

}

/* Display the records in the file */

void display()

{   

    emp3=(struct emp *)malloc(1*sizeof(struct emp));   

    emp3->emp_name=(char *)malloc(size*sizeof(char));

    int i = 1;

    if (fp1 == NULL)   

        printf("\nFile not opened for reading");

    while (i <= count)

    {

        fread(&emp3->emp_id, sizeof(emp3->emp_id), 1, fp1);

        fread(emp3->emp_name, size, 1, fp1);

        printf("\n%d %s",emp3->emp_id,emp3->emp_name);

        i++;

    }

    fclose(fp1);

    free(emp3->emp_name);

    free(emp3);

}

void update()

{

    int id, flag = 0, i = 1;

    char s[size];

    if (fp1 == NULL)

    {

        printf("File cant be opened");

        return;

    }

    printf("Enter employee id to update : ");

    scanf("%d", &id);

    emp3 = (struct emp *)malloc(1*sizeof(struct emp));

        emp3->emp_name=(char *)malloc(size*sizeof(char));

    while(i<=count)

    {   

        fread(&emp3->id, sizeof(emp3->emp_id), 1, fp1);

        fread(emp3->emp_name,size,1,fp1);

        if (id == emp3->emp_id)

        {

            printf("Enter new name of emplyee to update : ");   

            scanf(" %[^\n]s", s);

            fseek(fp1, -204L, SEEK_CUR);

            fwrite(&emp3->emp_id, sizeof(emp3->id), 1, fp1);

            fwrite(s, size, 1, fp1);

            flag = 1;

            break;

        }

        i++;

    }

    if (flag != 1)

    {

        printf("No employee record found");

        flag = 0;

    }

    fclose(fp1);

    free(emp3->name);        /* to free allocated memory */

    free(emp3);

}

$ a.out emprec1

1] Create a Record

2] Display Records

3] Update Records

4] Delete Record

5] Exit

Enter your choice : 1

Enter name of employee : aaa

Enter emp id : 100

Enter the name of the Department : Accounting

Enter Salary  : 15987.60

Enter Position: Audit manager

Enter Date of Joining: 10/3/2015

Enter your choice : 1

Enter name of employee : Ram

Enter emp id : 101

Enter the name of the Department : Management

Enter Salary  : 25987.60

Enter Position: Manager

Enter Date of Joining: 12/3/2015

Enter Your Choice : 1

Enter name of employee : Shyam

Enter emp id : 105

Enter the name of the Department : Management

Enter Salary  : 10987.60

Enter Position: Junior Manager

Enter Date of Joining: 10/4/2015

Enter your choice : 4

                             Section 2: C Programming Lab

Q.1.
A.1.(a)
DATA SEGMENT
        A DB 50H
        B DB 60H
DATA ENDS

CODE SEGMENT

        ASSUME DS:DATA,CS:CODE
        START:
                MOV AX,DATA
                MOV DS,AX

                MOV AL,A     
                MOV AH,B
                MOV BL,AL
                MOV AL,AH
                MOV AH,BL
                MOV A,AL
                MOV B,AH

                MOV AX,4C00H
                INT 21H

CODE ENDS
        END START

OUTPUT
***********

 BEFOR           AFTER
 ax 0000        ax 06C1

 bx 0000        bx CD36

Q.1.
A.1.(b)
DATA SEGMENT
X DW 27H
MSG1 DB 19,13,'NUMBER IS EVEN$'
MSG2 DB 10,13,'NUMBER IS ODD$'
DATA ENDS
CODE SEGMENT
ASSUME CS:CODE,DS:DATA
START: MOV AX,DATA
MOV DS,AX
MOV AX,X
TEST AX,01H
JNZ EXIT
LEA DX,MSG1
MOV AH,09H
INT 21H
JMP LAST

;Test for Even/Odd number.
;If it is Even go to Exit label.

Q.1.
A.1.(c)
Program 1:

MVI A, 32H : Store 32H in the accumulator

STA 4000H : Copy accumulator contents at address 4000H HLT : Terminate program execution

Program 2: LXI H : Load HL with 4000H MVI M : Store 32H in memory location pointed by HL register pair (4000H)


HLT : Terminate program execution

Q.1.
A.1.(d)
INCLUDE io.h

Cr EQU 0ah
Lf EQU 0dh


data SEGMENT
p_num DB cr, lf, 'Enter a number: ',0
p_rev DB cr, lf,'The reverse is: ',0
ten DW ?
tmpstr DW 40 DUP (?)
data ENDS



code SEGMENT
ASSUME cs:code, ds:data
start: mov ax, data
mov ds, ax
;input the number
output p_num
inputs tmpstr, 10
atoi tmpstr
;initialize
mov cx, 00h;stores the reverse number
mov ten, 10
;iterate to reverse digits
next: cmp ax, 0
jz op_rev;exit the loop if number=0
cwd
idiv ten;to extract units digit
mov bx, dx;to save contents of dx
xchg ax, cx;to perform multiplication
imul ten;to insert units digit
add ax, bx;add the acutal units digit
xchg ax, cx;save the reverse number back
jmp next
;output the reverse
op_rev: output p_rev
itoa tmpstr, cx
output tmpstr

quit: mov al, 00h
mov ah, 4ch
int 21h
code ENDS

END start